Perfect Cubes
$1, 8, 27, 64, 125, 216, 343, 512, 729$
Last Digit Pattern
$n^3$ ends in same digit as $n$ for:
$1, 4, 5, 6, 9, 0$
$2 \leftrightarrow 8$, $3 \leftrightarrow 7$ swap
Estimating ∛n
$$\sqrt[3]{n} \approx c + \frac{n - c^3}{3c^2}$$
$\sqrt[3]{30} \approx 3 + \frac{3}{27} \approx 3.11$
Powers of 2
$2, 4, 8, 16, 32, 64, 128, 256, 512, 1024$
Last digit of $\sqrt[3]{n}$ tells you last digit of answer!