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Business Calculus · Axiom Academy
EXAMPLE Total Revenue from Marginal Revenue Recovering revenue functions through integration 1 Tech Startup: Software Licenses A software company finds that their marginal revenue function for enterprise licenses is: where x is the number of licenses sold. The -0.5x² term shows diminishing marginal revenue - each additional license brings in less revenue than the previous one (volume discounts or market saturation). Maximum revenue occurs when MR = 0, i.e., when x = 400 licenses. 2 E-commerce: Subscription Service An online streaming service has marginal revenue: where x is subscribers in thousands. At 10,000 subscribers (x=10), monthly revenue is 85,000. Check: R(10) = -0.05(100) + 10(10) + (-10) = -5 + 100 - 10 = 85 ✓ The constant C = -10 represents the baseline adjustment. This could account for initial setup costs or free trial periods that reduce effective revenue when subscriber counts are low. A company knows MR(x) = 50 - 0.4x and wants to find the demand (price) function. Since R(x) = p · x, we have: p = x First find R(x), then divide by x to get the demand function p(x). The demand function p = 50 - 0.2x is linear. At x = 0, maximum price is 50. For each unit increase in quantity, price must drop by 0.20 to maintain demand. Unlike cost functions (which have fixed costs), revenue functions always satisfy R(0) = 0 because selling zero units generates zero revenue. This means the constant of integration is always 0. Based on the example above, which approach is correct?
This is the written version of the interactive lesson above. See the full Business Calculus course.